simplify
2006-11-16 08:39:39 · 8 answers · asked by chelsea y 1 in Science & Mathematics ➔ Mathematics
=(x-3)/8
2006-11-16 08:43:31 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Do you have all the brackets and parentheses in the right place? If so it can be: x - 9[x^3 - 3/8(1/x^2 - 1)]. I do not know if that helped but I do tutor math. Remember to do multiplication and division first.
2006-11-16 09:04:19 · answer #2 · answered by Blue-Eyed Guy 3 · 0⤊ 0⤋
(x-3)/8
2006-11-16 08:44:14 · answer #3 · answered by Atreides1998 3 · 0⤊ 0⤋
[(x - 3/2)^3]*[(1/(x -3)^2]
(x-3) cancels out twice
ANSWER
(x-3)/8
2006-11-16 08:43:14 · answer #4 · answered by trackstarr59 3 · 0⤊ 1⤋
what is x?
(x-1.5)^3 * (1/x -3)^2
thats the best it gets
2006-11-16 08:42:37 · answer #5 · answered by ibanezplayer9 2 · 0⤊ 1⤋
[(x - 3/2)^3]*[(1/x -3)^2]
=[{(2x - 3)/2}^3]*[{(1-3x)/x}^2]
={[(2x - 3)^3]/8}*[{(1-3x)^2}/x^2]
=[{(2x - 3)^3}*{(1-3x)^2}/x^2]/8x^2
2006-11-16 08:46:09 · answer #6 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋
(9x^3)-(93x^2/2)-(27/8x^2)+(216/x)+(48x)-(63/2)
2006-11-16 09:00:12 · answer #7 · answered by mane 5 · 0⤊ 0⤋
its math.. wizard or ex centric
2006-11-16 08:42:53 · answer #8 · answered by STORMY K 3 · 0⤊ 1⤋