Is it is as easy as taking the difference (in minutes) between sundown on the the longest day and the shortest day (adjusting for daylight savings) and then dividing this number by 182 (ie. the number of days in a half year)?
2006-11-16 08:25:24 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Weather
u can pray to god to give u d equation to calculate d intensity of d sun with snow also
2006-11-16 08:30:02 · answer #1 · answered by Maro E 3 · 0⤊ 1⤋
No. There's a trig function involved. But you can do what you want:
The rate of change in day length is greatest at the equinoxes and becomes zero and changes sign at the solstices. This is a trig function deal. You can take that change of which you speak and make it the min to max variation and use 1 year as the period. I'd recommed starting near my birthday, the Autumnal equinox and use a sin function. The sine function starting then has the right characteristics. Don't forget to use unit conversions so that the period of 2pi is 365.25 days. Have fun.
I did a solar engineering type problem where I used the variation of energy through the year. The trig function is very good.
Hey! I just realized something. Take a look at the analemma, or equation of time that's on most globes. It's that figure 8 looking thing. Study that for awhile. It's not what you want but it show interesting variation between clock time and solar time.
2006-11-16 16:40:18 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
well one way is to take a solar panel and a volt meter look at it at the same time every day then the more sunshine you get the more power you get see? so if you see how much it gives off everyday at the same time making sure the thing hasnt moved then you will be able to tell by see how much volts thier are every day ( depending on the weather of course) now to figure out how much left see how much its changed after like say a week and then calculate how much energy lose every day then see how much energy left till 0 or absolute no sunshine thats the awnser
im sorry i have to go but ill give you the equations tomorow promise
2006-11-16 16:42:06 · answer #3 · answered by sean02744 1 · 0⤊ 0⤋
No it's a very complex formula that sort of looks like a sine wave (waves traveling down a string) and depends very heavily on your latitude.. By the way, the analema mentioned below tells how astronomical noon differs from noon on the clock. It has nothing to do with duration of sunlight in a day.
2006-11-16 16:29:48 · answer #4 · answered by Gene 7 · 0⤊ 0⤋