2006-11-16 07:43:50 · 11 answers · asked by chelsea y 1 in Science & Mathematics ➔ Mathematics
A least common multiplier means the maximum value of the numbers after mulplication of each number. Therefore the answer is 5ab
2006-11-16 07:52:04 · answer #1 · answered by Thilina Guluwita 4 · 3⤊ 0⤋
when you consider that human beings replied the question yet did not clarify a thanks to discover the answer, i will inform you techniques to outline the answer. The least without delay ahead denominator is the bottom denominator that each and each and every body the denominator that each and each and every body the style's will divide into flippantly. for example, both a million/3 and a million/5 will divide into a million/15, yet a million/10 gained't divide flippantly. a million/5 will divide into a million/10 flippantly, yet a million/3 gained't. to discover one which each and each and every body 3 of your fractions will divide into, in case you multiply a million/10*a million/3*a million/5, you receives a million/one hundred and fifty. yet there are decrease numbers that each and each and every body of the above fractions will divide into, so as that could not the least without delay ahead denominator. 30/10=3 30/3=10 30/5=5 subsequently, your answer is a million/30
2016-11-24 22:57:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
LCD=5ab
3/a=15b/5ab
3/b=15a/5ab
1/5=ab/5ab
2006-11-16 07:47:10 · answer #3 · answered by yupchagee 7 · 1⤊ 0⤋
To find the LCD of 3/a, 3/b,1/5
i.e. 15a 15b 15
i.e. 15a= 3x5a 15b=3x5b 1x5 Prime factors of each number
i.e. 3x5a 3x5b 1x5Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs
i.e. 5ab
2006-11-16 09:20:47 · answer #4 · answered by Prabhakar G 6 · 1⤊ 0⤋
a*b*5
2006-11-16 07:47:22 · answer #5 · answered by gggjoob 5 · 3⤊ 0⤋
There are no common factors of a, b, and 15, so the LCD = 15ab
2006-11-16 07:53:24 · answer #6 · answered by Helmut 7 · 1⤊ 0⤋
5ab
so if you multiply each of them out you would get
15b/5ab,15a/5ab,ab/5ab
2006-11-16 07:46:36 · answer #7 · answered by popnbrown 2 · 2⤊ 0⤋
That would be 5ab:
15b,15a,3ab
2006-11-16 08:29:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋
5ab
2006-11-16 07:45:32 · answer #9 · answered by Meemah 3 · 3⤊ 0⤋
ab5
2006-11-16 08:17:07 · answer #10 · answered by mane 5 · 2⤊ 0⤋