-4r(squared)=21r=r+13
i need the zeroes... and i cant seem to figure it out
2006-11-16 07:40:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = "
it must be something like this
-4r ² ± 21r=r+13
Good Luck
2006-11-16 07:53:47 · answer #1 · answered by sweetie 5 · 4⤊ 0⤋
-4r(squared)=21r=r+13
-4r^2=21r=r+13
I think there is a typo. There should only be 1 = here.
2006-11-16 15:44:23 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
You must have a typo because this does not work.
(-4r)^2 = 21r
16r^2 = 21r
r = 21/16
then
21r = r + 13
21 * (21/16) = (21/16) + 13
441/16 = 220/16 ?????
2006-11-16 16:13:03 · answer #3 · answered by FabMom 4 · 0⤊ 0⤋
sure a typo
pls retype the question
2006-11-16 16:23:06 · answer #4 · answered by mane 5 · 0⤊ 0⤋
766548=67r=34241616^200000000000000000000000000000 dats ur answer
2006-11-16 15:44:53 · answer #5 · answered by Maro E 3 · 0⤊ 0⤋