2006-11-16 07:13:37 · 6 answers · asked by ♥ kellycakes ♥ 1 in Science & Mathematics ➔ Mathematics
AD is larger than BC, and the two sides are opposite one another, but the legs of the isosceles trapezoid are congruent. AD and BC must be the parallel sides. The midsegment of an isosceles trapezoid is equal to the average of the two parallel sides, so (AD + BC) / 2 = EF.
AD + BC = 2EF
(30x + 12) + (17x) = 2(22.5x + 9)
47x + 12 = 45x + 18
2x = 6
x = 3
AD = 30x + 12 = 30(3) + 12 = 102
2006-11-16 08:12:39 · answer #1 · answered by Clueless 4 · 0⤊ 0⤋
hi something is inaccurate good the following, pls recheck your question , if its a Isosceles trapezoid as u say then BC=ad the position 17x=30x+12 which will grant x= -(12/13) which could't be genuine.
2016-11-29 05:02:05 · answer #2 · answered by ? 4 · 0⤊ 0⤋
hi something is wrong here, pls recheck your question , if its a Isosceles trapezoid as u say then BC=AD
where 17x=30x+12
which will give x= -(12/13) which cannot be true.
2006-11-16 08:35:52 · answer #3 · answered by mane 5 · 0⤊ 0⤋
AD = 30X + 12.
2006-11-16 07:26:08 · answer #4 · answered by Product of Conception 3 · 0⤊ 0⤋
Do your own homework.
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2006-11-16 07:15:02 · answer #5 · answered by Drofsned 5 · 0⤊ 0⤋
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2006-11-16 07:22:55 · answer #6 · answered by cujimmy57ok 2 · 0⤊ 1⤋