Do a prime factorization of each number:
18 = 2 x 3 x 3
30 = 2 x 3 x 5
42 = 2 x 3 x 7
The prime factors they have in common are a two (2) and a three (3).
2 x 3 = 6
GCF(18, 30, 42) = 6
2006-11-16 04:59:09
·
answer #1
·
answered by Puzzling 7
·
2⤊
0⤋
The greatest common factor of a set of numbers is the largest number that will divide into all of them.
Star by finding the prime factors ( prime numbers that will divide into the different numbers you are given).
8 = 2 x 3 x 3
30 = 2 x 3 x 5
42 = 2 x 3 x 7
Each of these numbers contains 2 x 3 as common factors. Multiply these common factors together to get the greatest common factor
2 x 3
=6
2006-11-16 05:03:16
·
answer #2
·
answered by rosie recipe 7
·
0⤊
0⤋
6
2006-11-16 05:08:16
·
answer #3
·
answered by Steve P 5
·
0⤊
1⤋
6
2006-11-16 05:05:14
·
answer #4
·
answered by openpsychy 6
·
0⤊
1⤋
18 = 2*3*3
30 = 3*2*5
42 = 2*3*7
so the greatest common factor is 2*3 because these are the primes they have in common.
2006-11-16 04:58:59
·
answer #5
·
answered by xian gaon 2
·
0⤊
0⤋
18=2*3*3
30=2*3*5
42=2*3*7
so GCF = 2*3 =6
2006-11-16 05:00:37
·
answer #6
·
answered by grandpa 4
·
0⤊
0⤋
it is 6
2006-11-16 04:56:58
·
answer #7
·
answered by raj 7
·
0⤊
1⤋
18= 2*3*3
30=2*3 *5
42=2*3*7
The greatest number common to all three numbers is 3
2006-11-16 04:59:47
·
answer #8
·
answered by ironduke8159 7
·
0⤊
1⤋
6 and the average of 30!
2006-11-16 05:04:27
·
answer #9
·
answered by namazanyc 4
·
0⤊
1⤋
Um; parent them out your self. it is not that perplexing. what's the optimal quantity that could pass into all of them? what's extra is which you would be able to component them then locate the aspects that each have. the 1st one is 4.
2016-10-22 05:00:15
·
answer #10
·
answered by connely 4
·
0⤊
0⤋