apparent minus absolute magnitude is the distance...?

Answer 1

In astronomy, absolute magnitude is the apparent magnitude, m, an object would have if it were at a standard luminosity distance away from us, in the absence of interstellar extinction. It allows the overall brightnesses of objects to be compared without regard to distance.

The apparent magnitude (m) of a star, planet or other celestial body is a measure of its apparent brightness as seen by an observer on Earth. The brighter the object appears, the lower the numerical value of its magnitude.

These answers come from Wikipedia:
http://en.wikipedia.org/wiki/Apparent_magnitude
http://en.wikipedia.org/wiki/Absolute_magnitude
and these sites may have additional info helpful to you.

Hope this helps!

Answer 2

With dimensions of light years, your first equation is authentic: M = m - 5((log DL/3.2616) - a million ) the position the log is to the bottom 10 the three.2616 converts the length from parsecs to lightyears that you want to insert. Log DL is the log of base 10 of DL, or the potential to which 10 must be raised to get DL ( if DL = 1000 then log DL = 3 ).

Answer 3

False.

Answer 4

... modulus.

http://en.wikipedia.org/wiki/Distance_modulus