ok i got two questions this time
the directions say
Write an equation of the line that passes through each pair of points
the q's r
(8,-1) (7,-1)
and
(-3,-5) (3,-15)
2006-11-16 04:18:09 · 3 answers · asked by jimmy 2 in Science & Mathematics ➔ Mathematics
the formula is (y-t1)/(y2-y1)=(x-x1)/(x2-x1)
1.sub
y+1/-1+1=(x-8)/(7-8)
-1(y+1)=0(x-8)
-y-1=0
=>y+1=0
2.y+5/-15+5=(x+3)/3+3
6(y+5)=-10(x+3)
6y+30=-10x-30
adding 10x+30
10x+6y+60=0
dividing by 2
5x+3y+30=0
2006-11-16 04:23:48 · answer #1 · answered by raj 7 · 0⤊ 0⤋
leteq.be ax+by+c=0
put (8,-1)
8a-b+c=0...(1)
put(7,-1)
7a-b+c=0.....(2)
solve (1) &(2) for a and b
in terms of c
u get
a=0
b=-c
put these values in ax+by+c=0
-cy+c=0
y-1=0
2006-11-16 04:26:11 · answer #2 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋
let the pts be (x1,y1),(x2,y2)
then eq of line is
(x-x1)/(y-y1)=(x2-x1)/(y2-y1)
2006-11-16 04:23:32 · answer #3 · answered by . 3 · 0⤊ 0⤋