If a metal ball is falling with acceleration of 10 what is its average speed?

Question

There is a metal ball which is falling with the acceleration 10 and now tell what is its average speed?

There is a metal ball has been falling for 5 seconds with the acceleration of 10 from a height of 125 m what is its average speed?

Answer 1

The change in velocity of an object undergoing uniform acceleration, a, for a given time, t, is given by:
v = at
where v is the change in velocity of the object.

If the object is accelerating at a constant rate of 10 m/s^2 for 5 seconds, the change in velocity the object experiences is 50 m/s.
Since (we assume) the object started from rest, the objects final velocity after 5 seconds is 50 m/s.

To find the average velocity, divide the total displacement of the object by the total time.
In this case, the object has traveled 125 meters in the 5 seconds it has been accelerating (d = 1/2 at^2), so dividing this by 5 seconds and we get an average velocity of 25 m/s.

Answer 2

If the ball fall for 5 seconds with an acceleration of 10, then the total distance it falls (assuming it begins at rest) is
x = 1/2 * a * t^2
= 1/2 * 10 * 5^2
= 125
The average velocity is the distance it travels divided by the time it travels:
Vavg = 125 / 5
= 25

Answer 3

Depends how far it is falling. A falling object will accelerate until it reaches terminal velocity. If it falls only a short distance it won't reach terminal velocity and the average speed will be low. If it falls a long distance then it will spend most of it's fall at or near terminal velocity and the average will also be closer to that speed.

Answer 4

Use the mean value theorem, 1/(b-a)(Integral from 0 to what ever time of the acceleration equation)

Answer 5

17.5 mph
or 65 kph.

-HtJ