2006-11-16 04:08:01 · 5 answers · asked by cabo 1 in Science & Mathematics ➔ Mathematics
5.00/0.5 = 1 to 10 dilution
600/10= 60 mL of stock needed
the rest (540mL) is water
2006-11-16 04:13:59 · answer #1 · answered by orca1006 2 · 0⤊ 0⤋
let x= volume of 5M HNO3 required
then 600-x = volume of watwer required
now do a HNO3 balance
x*5+ (600-x)*0 = 600*0.5
x = 300/5 = 60
so 5M HNO3 required = 60 ml
water required = 600-60= 540 ml
2006-11-16 13:18:10 · answer #2 · answered by grandpa 4 · 0⤊ 0⤋
V1M1=V2M2
V1*5=600*0.5
V1=60ml
2006-11-16 12:26:59 · answer #3 · answered by . 3 · 0⤊ 0⤋
V1*C1 + V2*C2 = Vt * Ct
(X)(5) + (600-X)(0) = 600(.5)
5X = 300 X=60
60 ml HNO3 and 540ml H2O
2006-11-16 12:20:14 · answer #4 · answered by davidosterberg1 6 · 1⤊ 0⤋
hi you made it look pretty easy
2006-11-16 12:19:21 · answer #5 · answered by raj 7 · 0⤊ 0⤋