(3y-5)+(5y+20)=135
=.3y-5+5y+20=135
=>3y+5y=135+5-20
=>8y=120=>y=120/8=15
2006-11-16 03:57:44
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answer #1
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answered by alpha 7
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(3y - 5) + (5y + 20) =135
Step 1: Rearrange
3y + 5y - 5 + 20 = 135
Step 2: Add
8y + 15 = 135
Step 3: Group the numbers on the right side of the equation
8y = 135 - 15
8y = 120
y = 15
2006-11-16 12:15:02
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answer #2
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answered by Turtle 2
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(3y - 5) + (5y + 20) = 135
3y - 5 + 5y + 20 = 135
3y + 5y = 135 + 5 - 20
8y = 120
8y/8 = 120/8
y = 15
to check:
(3y - 5) + (5y + 20) = 135
3y - 5 + 5y + 20 = 135
3(15) - 5 + 5(15) + 20 = 135
45 - 5 + 75 + 20 = 135
135 = 135
2006-11-16 12:30:23
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answer #3
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answered by Anonymous
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first distribute what's inside the ().
=> 3y - 5 +5y +20 = 135
then you want to isolate the variable, which in this case happens to be y.
in order to do so you have to add 5 to both sides and subtract 20 from both sides.
=> 3y +5y = 135 + 5 - 20
Now you combine all the like terms:
=> 8y = 120
You have still not isolated y so you must now divide by 8.
=> y = 120 / 8
you can simplify this even more:
since both numbers are divisible by 8
120 / 8 = 15 and 8 / 8 = 1
you get => y = 15 / 1 which ultimately equals 15.
2006-11-16 11:56:50
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answer #4
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answered by awesome! 1
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3y -5 + 5y + 20 = 135
8y = 135 +5 - 20
8y + 120
y = 15
2006-11-16 11:49:53
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answer #5
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answered by Anonymous
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(3y - 5) + (5y + 20) = 135
(3y - 5) + 5y + 20 = 135 ....................open the second bracket
3y - 5 + 5y + 20 = 135.....................open all the brackets
3y + 5y - 5 + 20 = 135
3y + 5y = 135 + 5 - 20...arrange'em with same unknown
8y = 120
y = 120/8
y = 40
2006-11-16 11:55:09
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answer #6
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answered by a m a l 2
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3y-y+5y+20=135
8y+15=135
adding -15
8y=120
divivding by 8
y=120/8
=15
2006-11-16 12:02:04
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answer #7
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answered by raj 7
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y = 15
2006-11-16 11:59:02
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answer #8
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answered by princessmandy55555 1
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ignore the parenthesis and add like terms
8y + 15 = 135
get the variable by itself
8y=120
y=15
2006-11-16 12:05:55
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answer #9
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answered by Renee G 2
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8y+15=135
8y=120
y=15
2006-11-16 11:56:02
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answer #10
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answered by Anonymous
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