IN ALACHUA COUNTY APPROXIMATELY 50% OF VOTERS ARE DEMOCRATS, 28% REPUBLICANS, AND THE REMAINEDER OTHER PARTIES OR NOT AFFILIATED WITH ANY PARTY. YOU CONDUCT A POLL BY CALLING REGISTERED VOTERS AT RANDOM.
1. WHAT'S THE PROBABILITY THAT THE FIRST FOUR VOTERS YOU CALL ARE NEITHER DEMOCRAT NOR REPUBLICAN?
2. WHAT THE PROBABILITY THAT AT LEAST 1 OF THE 4 VOTERS YOU CALL ARE REPUBLICAN?
2006-11-16 02:31:30 · 3 answers · asked by trinidadgyrl 1 in Science & Mathematics ➔ Mathematics
1. 50+28=78 so 22% are neither. Multiply 22/100 X 22/100 X 22/100 X 22/100 because you need four voters.
2. You should find the probability that none are, then subtract from 1.
The prob that someone is not Republican is 100 -28 or 72%
So 72/100 X 72/100 X 72/100 X 72/100 is probability of no Republicans. Find this and subtract it from 1 so get P(at least 1 Rep.)
2006-11-16 02:37:15 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
If you conduct a poll by CALLING. You introduce some interesting sampling errors.
1. Are republicans more likely to to have phones than deomcrats?
2. Are they more likely to have unlisted numbers?
3. Are democrats more likely not answer the phone bacause thay need three full time jobs just to pay the rent/food/gas?
2006-11-16 11:03:33 · answer #2 · answered by disco legend zeke 4 · 0⤊ 0⤋
voters for other parties are 22%
1.
the first four belong to 22%
hence 22c4/100c4
2.
in those 4 one is republican and 3 are others
hence 28c1*22c3/100c4
2006-11-16 10:38:47 · answer #3 · answered by . 3 · 0⤊ 0⤋