physics assignment #3.. please help me. please. thanks for those who answered!!?

Question

a grandprix racer completes a 500km race in exactly 2hr and 15mins. wat is d average speed in km/hr and m/sec

Answer 1

just use the formula avg.speed=distance/time
for km/hr change time to 2.25 hr
and for m/sec change distance to 500000m and time to 135*60sec
do these ques yourself. in exams you won't have yahoo answers
:)

Answer 2

properly I regarded it throughout and it seems high-quality different than for here: 2) you have 25.5 km. i'd say 25 km through certainty which you're limited to 2 considerable digits. 4) I agree along with your acceleration. Your known velocity is incorrect. I define 2 procedures, you are able to only situation your self with the 1st. the 2d is that in case you're curious. a million) known velocity = distance traveled/ time you are able to desire to be sure the complete distance traveled. there's a simplified kinematic equation for this: d(distance traveled) = Vi*t (preliminary velocity x time) + a million/2 a *t^2 (acceleration x time squared) Substituting our values we get d= a million/2 * 5.4/12 * (12)^2= 32.4 m We then divide this distance by potential of our complete time to get the known velocity of two.7 m. 2) Calculus technique (option answer): So in case you graph velocity as against time you will have a at as quickly as line going from the component (0 s, 0 m/s) to (12 s, 5.4 m/s). all of us be attentive to that the fundamental below this line is the complete distance traveled. through fact it somewhat is a triangle, our equation for distance d= a million/2 (b) (h) = a million/2 (5.4 m/s) (12 s) = 32.4 m. known velocity = d/t, 32.4/ 12 = 2.7.

Answer 3

AVG speed = 500,000 meters/(135*60)"this is to comvert the kilometers/hour to meters second"
=61.728395061728395061728395061728meters per second
rounded off to 61.73meters per second
into kilometers
speed in meters/second*(60seconds*60seconds"to give time in hours")/time taken to travel 61.73meters that is one second

=61.73m/s*3600/1=222228kilometers/hour(pretty fast)

but the normal culculation to find the average speed is
(final speed-initial speed)/total time taken

but since it seemed to accelerate from rest then in the place of initial speed its value is zero

Answer 4

15mins = 0.25hours

t = 2.25h
s = 500km

S = V * t

V = S / t

V = 500km / 2.25h = 222.22km/h
Average speed = 222.22km/h

Answer 5

average speed = 500/2.25 = 222.22 km/hr = 6.17 m/sec

Answer 6

avg speed = 222.22 km/ hr

Answer 7

500000/135 this is the answer in m/sec