If I jump from a great height how will far will I fall before I reach maximum speed?

Answer 1

Your terminal velocity (the velocity where air resistance equals the force of gravity, so that you no longer accelerate) depends on your surface area to volume ratio (assuming we are all roughly the same density). This is because drage scales with area, while mass (and hence the force of gravity) scales with volume.

For a typical adult, terminal velocity is around 200km/h (about 124 miles/h). This is about 55 m/s so you will reach it in around 6 seconds.

Answer 2

The maximum speed is termed as Terminal Velocity, Vt.
When an object moves through a fluid, gas or liquid, it experiences a drag force. For low speeds and small dimensions of the object this drag force is proportional to the velocity, but for larger, irregularly shaped objects this drag force is proportional to the square of the velocity, which can be expressed by the formula;

R = 0.5C(rho)Av^2
Rho is the density of air or any fluid
C is a dimensionless quantity called the drag coefficient.
A is the cross-sectional area of the falling object.


A falling object experiences two oppositely directed forces, namely the weight, mg, which is downward, and the drag force, R, which is upward. so the net force will be
Fnet = mg - 0.5C(rho)AV^2
But Fnet = ma
ma = mg - 0.5C(rho)AV^2
or
a = g - [0.5C(rho)AV^2]/m
at terminal velocity, both forces balance each other and therefore net force and hence accelleration is = 0
0 = g - [0.5C(rho)AVt^2
or
Vt = sqrt[2mg/C(rho)A]
For a person falling from a great height, the terminal velocity is approximately (58 - 60)m/s

Answer 3

Putting it simply there are two factors to consider.
(1) Your height from the ground. Your will reach your maximum speed at the moment you strike the ground, provided you don't reach terminal velocity.
(2) If you are high enough, you will reach terminal velocity and that will be you top speed.

So it's which ever comes first.

The distance you travel before reaching your top speed will be dictated by your height if it's a short distance.
If you are high enough then the distance you travel before reaching your top speed will depend on your body size and eddy currents.

Answer 4

I believe there are a few differant factors involved to concider when you ask this question. Are you falling in a seted position? standing? belly floping? or Diving? Each will determin differant volosity. Also it matters how much you weigh and where in the world this fall takes place, because of the earths gravitational pull. but I think its around 70 to 80 miles per hour max speed at about 1/2 a mile

Answer 5

after jumping you will be free - falling with the accelerator of g = 10
your speed will keep increasing, so if there is no obstacle, your speep will increase to infinity. otherwise , we have :
y= 1/2 gt^2
v = gt
when you reach the land, you will reach the maximum speed right before landing .
y_max = h = 1/2 gt_max^2 => t_max = square root of (2*h_max / g)
v_max = g*t_max

all units must be in SI

Answer 6

the optimum speed of a falling merchandise is it relatively is terminal speed. that's while the downward rigidity of gravity precisely equals the upward rigidity of air resistance, so there is not any internet rigidity on the object, and it falls at a relentless speed. The previous remark that cats continuously look to land on their ft has to do with the cat's terminal speed. while falling from an incredible top (say, 5 thoughts), the cat can rather substitute it relatively is terminal speed by utilising spreading it relatively is legs to extend it relatively is air resistance, for that reason slowing it down. they are able to truly fall from very extreme and run away unscathed.

Answer 7

The limit lies in how far you fall aswell. It si the same principle used to keep satelites in motion bout the earth....dont know the formula though. That's ofcourse in practical cases.

Theoretically, use this formula.... v=u +at

v=c=speed of light
u=0
a=g=acceleration due to gravity
t=time to be found out

so the equation is : t= c/g

Ofc the above equation works only in theoretical cases...it is practically imposiible