2006-11-15 18:32:58 · 9 answers · asked by ram 1 in Science & Mathematics ➔ Weather
-40 degrees fahrenheit is equal to -40 degrees celcius
2006-11-15 18:35:53 · answer #1 · answered by phn0rd 2 · 1⤊ 0⤋
The conversion formula is c = (f-32) * 5/9 => 9c = 5f - (32 * 5) =>9c = 5f - 160. but we want the special condition of c = f to apply. That implies 9c = 5c -160 => 4c = -160 => c = -40. Now check: c = f = -40. c = (f -32) * 5/9 => --40 = (-40 - 32) * 5/9 = -72 *5/9 = -360/9 = -40. qed.
2006-11-16 03:15:14 · answer #2 · answered by flyfisher_20750 3 · 0⤊ 0⤋
This is a simple algebraic problem.
F = Fahrenheit temperature
C = Celsius (or for us old timers, Centigrade) temperature
C = (F-32) * 5/9 ........is the conversion formula
9C = (F-32) * 5 ........multiply both sides by nine
9C = 5F - 160 ...........remove parenthesis
C = F ........................is the condition we want to find.
5C = 5F ......................multiply both sides by five.
9C - 5C = 5F - 5F - 160 ....subtract one equation from the other
4C = -160 ..........................reduce
C = -40, and F = -40
And that's the only temperature where both systems are the same... but that temperature is so cold that you won't care which system is in use!!!
2006-11-16 02:53:06 · answer #3 · answered by Irma R 2 · 0⤊ 0⤋
9x/5 + 32 = x
9x + 160 = 5x
4x = -160
x = -40°F = -40°C
2006-11-16 02:37:16 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
-40 +40
2006-11-16 03:42:07 · answer #5 · answered by rony h 1 · 0⤊ 1⤋
-40 degrees.
2006-11-16 02:36:05 · answer #6 · answered by Anonymous · 0⤊ 0⤋
- 40
solution: (x-32) / 9 = x/5 --> x = - 40
2006-11-16 02:35:49 · answer #7 · answered by orca1006 2 · 1⤊ 0⤋
they will never equal. look at the conversion formula
2006-11-16 02:35:23 · answer #8 · answered by icantfindaname50 2 · 0⤊ 1⤋
-40F = -40C
2006-11-16 02:36:17 · answer #9 · answered by hockey 2 · 0⤊ 0⤋