Math Question?

Question

Once there was 7 dogs. They were called A, B, C, D, E, F, and G. A, B, and C are the oldest. Their total weights equal the same as the youger ones (D, E, F, and G).

1. C is 2 oz more than B, who is 6 oz more than A.
2. F is 12 oz more than G, who is 3 oz more than E and 13 oz more than D.
3. B and F are about the same weight except B is a bit heavier.
4. It the kittens' weights are all in whole oz, what is the least that each kitten could weigh and still meet the requirements

Please show your steps show I can see how you did it. If you answer me saying do my homework, well I'am trying....?! But I don't get it.... Can someone please help me.

I meant dogs at the end

Answer 1

Ok, I'll help you out, but I'm not going to give you an answer because I'm not going to do the work. Besides, you were pretty sloppy here, calling dogs kittens and #3 makes no sense if you're talking about whole oz. So reword that ridiculous statment to say that dog B weighs EXACTLY the same as dog F.

First thought, always: "How many unknowns do I have"

You have seven: A-G

Second thought, always: "I MUST have 7 different equations or I cannot solve the problem."

Note: In this problem if you have less than 7 different independent equations, it is IMPOSSIBLE to solve the question (that is, without some other constraint. For example if you had some problem asking you to find the total number of puppies in the kennel, and the numbers worked out you'd have 2 puppies or 0.5 puppies, you have to go with 2 because you can't have half a puppy unless you're a sicko).

Ok, you need 7 equations. Start writing.

A+B+C = D+E+F+G

C=B+2=A+6
F=G+12=E+3=D+13
B=F

There are your seven equations. I leave it to you to understand fully where those seven come from. From here, you start substituting, until you get the first equation in terms of one single variable. Without giving it too much thought, I would suggest "F". Solve for that one variable, then solve for the other variables. Since you have 7 equations and 7 unknowns, there is no "minimum" weight: you will have the exact weight of the kittens.

Answer 2

let the wt. of A be x oz.
Therefore,the wt ofB=x+6 , and
the weight of C=x=6=2=x+8 oz.
Let the wt. of D=y oz.
then,the wt. of G=y+13
wt of E=y+13-3=y+10
wt of F=y+13+12=y+25
by the problem,x+x+6+x+8=Y+Y+10+y +25+y+13
=>3x+14=4y+48
=>3x-4y=34.........(equn. 1)
it has been given that B and F are almost the same weight
=>x+6=y+25
=>x=y+19
Putting the value of x in equation no. 1 we get y=23 oz.
Therefore x=23+`19=42 oz
Therefore their weights are
A=42 oz
B=42+6=48 oz
C=42+8=50oz
D=23 oz
E=23+10=33oz
F=23+25=48 oz and G=23+13=36 oz.

Answer 3

No requirements listed for kittens.
Only information is partial for the puppies.

problem is incomplete

now can we go order pizza?

Answer 4

You are supposed to be learning. Use your brain and solve it yourself!