the
a)frequency remains the same, but the wavelength is shortened, compared to the emitted radiation.
b)detected wavelength is longer than the emitted wavelength.
c)speed of the radiation is reduced below the emitted speed.
d) measured frequency is higher than the emitted frequency.
2006-11-15 17:23:53 · 4 answers · asked by diente 1 in Science & Mathematics ➔ Astronomy & Space
(a) wrong -- the speed of light is constant, and the velocity of a wave is equal to wavelength*frequency... so this will always equal to the same number so you cannot change one without changing the other
(b) this is correct because as something is moving away and emiting light the velocity of the light doesn't change so it is shifted (the wave expands horizontally -- or in the direction of the motion)
(c) speed of light is constant
(d) wavelength is going up so frequency is going down.... here is a nice graph: http://archive.ncsa.uiuc.edu/Cyberia/Bima/Images/CBCSpec_lg.jpg
2006-11-15 17:50:28 · answer #1 · answered by xian gaon 2 · 0⤊ 0⤋
a, of course.
I'm sure about that.
I'm willing to sacrifice my life if my answer is incorrect.
2006-11-16 02:05:10 · answer #2 · answered by jdash01 3 · 0⤊ 0⤋
b
2006-11-16 04:19:19 · answer #3 · answered by Todd D 3 · 0⤊ 0⤋
b)
2006-11-16 01:33:55 · answer #4 · answered by gp4rts 7 · 0⤊ 0⤋