Anyone good with physics that could help me?

Question

I could really use any help on this problem that anyone could give me. Thanks in advance. I will give 10 points if anyone can help me out.

A space station shaped like a giant wheeel has a radius 96 m and a moment of inertia of 5.08 108 kgm2. A crew of 150 lives on the rim, and the station is rotating so that the crew experiences an apparent acceleration of 1 g (there is a figure linked at the bottom). When 100 people move to the center of the station for a union meeting, the angular speed changes. What acceleration is experienced by the managers remaining at the rim? Assume that the average mass of each inhabitant is 65.0 kg. The answer is in m/s squared

http://www.webassign.net/sercp/p8-54.gif

Answer 1

EDITED 11/16

First remember that angular momentum is conserved. The angular momentum is I*w, where I is the moment of inertia and w the angular velocity. When 100 move to the center the moment of inertia changes; initially there was a mass of 100*65kg at radius 96m that vanished (assuming they moved to radius 0). The change in moment is that mass times r^2. Therefore w must increase by that proportion; I assume that 5.08*10^8 is the moment of the space station alone. Add to that the moment of the crew = 150 * 65 * 96^2 to get the full moment before the move I1; I2 is the moment after the move, I2 = I1 - 100*65*96^2. Take the ratio I2/I1 and divide into the initial angular velocity w0. w0 is found from the radial acceleration at the rim which is w0^2*r = 1g,
so w0 = √[g/r]. The new angular velocity is w1 (figured from change in moment above). The new acceleration at the rim is then w1^2*r