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how do you do this math problem: find the value of each variable in the polygon...well, there are 4 angles, 2 of them with missing values. the values shown are 100 degrees and 60 degrees. the missing values are dubbed 'm degrees' and '3m degrees'...so how do you solve this?

2006-11-15 15:04:50 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

m+3m+100+60=360*
4m+160=360
adding -160
4m=200
dividing by 4
m=50
the unknown angles are
50* and 150*

2006-11-15 15:11:18 · answer #1 · answered by raj 7 · 0 0

The (4) angles in this polygon indicate
that the figure is a quadrilateral (a four-sided figure).
The (4) interior angles in ANY quadrilateral total 360 degrees.
The (2) values you are given are 100 and 60 degrees. They total 160 degrees. This leaves a balance of 200 degrees (360-160=200). Therefore 200=m+3m.....or 200=4m.....therefore
200/4=m......soooooo m=50 degrees and 3m=150 degrees.

2006-11-15 15:18:04 · answer #2 · answered by popcorn 3 · 0 0

all the angles should add up to 360 so set up an equation

we already know 100 + 60 is 160 and 3m + m is 4m
so its 160 + 3m = 360
4m=200
m=50

2006-11-15 15:14:18 · answer #3 · answered by lakersforlife 3 · 0 0

For regular polygons, the angles add up to 180, 360, 540, 720, etc, for triangles, squares, pentagons, hexagons, etc.

So your polygon is a square with the sum of all angles=360; the remaining two add up to 360-160=200. m+3m=200; 4m=200; m=50.

2006-11-15 15:17:21 · answer #4 · answered by hznfrst 6 · 0 0

you know that all the angles of a polygon need to add up to 360, so you do 360-160=m+3m

(the 160 is the sum of the 2 given angles).
and then you know that 200=4m so m=50. so the missing angles are 50, and 150. done.

2006-11-15 15:07:15 · answer #5 · answered by brookbabe90 5 · 2 1

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