How would I go about calculating the volume occupied by 5.8 g of propane gas (C3H8) at 23 degrees Celsius and 1.15 atm pressure?
do I use PV=nRT (V=nRT/P)? I'm not sure how to get n though...I know it's number of moles...so is it just 5.8 g/44 g (molecular weight of C3H8)?
2006-11-15 14:54:11 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
yes, PV=nRT
yeah, 5.8g / 44g = # of moles
^the guy above me is talking about milli-moles... but your R value is probably given in moles
2006-11-15 15:05:11 · answer #1 · answered by fleisch 4 · 0⤊ 0⤋
That will work if the R you are using is based on gram-moles. If the R you are using is Kg-moles then you will need to divide 5.8/ 44 by 1000.
Check the units of R.
2006-11-15 15:03:43 · answer #2 · answered by Roadkill 6 · 0⤊ 0⤋
Yes, that is how you get it. Just be sure your gas constant is in the right units.
A good rule of thumb is that for ideal gas problems use .08206 Latm/mol and for physical properties (ie Energy) use 8.314 J/molK.
2006-11-15 16:38:16 · answer #3 · answered by jessejames5769 2 · 0⤊ 0⤋