How large a force is required to accelerate a 1600 kg car from rest to a speed of 25 m/s in a distance of 200 m?
a. 1600 N
b. 0 N
c. 200 N
d. 2500 N
2006-11-15 14:30:15 · 2 answers · asked by SMS 1 in Science & Mathematics ➔ Physics
The average veocity of the car from 0 to 25 m/s is 12.5 m/s.
The total amount of time it takes is 200 m / (12.5 m/s) = 16 seconds.
The change is speed in 16 seconds is from 0 to 25 m/s. Therefore, the acceleration is (25 m/s)/ (16 s) = 1.5625 m/s^2
The force = mass * acceleration = 1600 kg * 1.5625 m/s^2 = 2500 N
Answer is d.
2006-11-15 16:19:57 · answer #1 · answered by tedhyu 5 · 0⤊ 0⤋
well, remember F=ma, this problem will combine mechanics with forces.
V^2 = V0^2 + 2ax
25^2 = 0 + 2(a)(200)
625 = 400 a
a = 625/400 = 1.5625
F = ma = 1600 kg (1.5625 m/s^2) = 2500 N
2006-11-15 23:05:49 · answer #2 · answered by Brian B 4 · 0⤊ 0⤋