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2006-11-15 12:20:37 · 2 answers · asked by amy B 1 in Science & Mathematics Chemistry

can you show me the calculations please

2006-11-15 12:32:54 · update #1

2 answers

For BaF2 Ksp=1.84*10^-7

If s is the molar solubility of BaF2 then

... .. .. .. BaF2 <=> Ba(+2) + 2F(-)
Dissolve.. s
Produce .. .. .. .. . .. .. s .. .. .. 2s

Ksp=[Ba+2][F-]^2= s*(2s)^2= 4s^3 = 1.84*10^-7 =>

s =((1.84*10^-7)/4)^(1/3)= 3.6*10^-3

so [F-]=2s= 2*3.6*10^-3= 7.2*10^-3 M

2006-11-15 21:58:27 · answer #1 · answered by bellerophon 6 · 0 0

About 38 g/L

2006-11-15 12:29:07 · answer #2 · answered by ? 2 · 0 0

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