Can someone helps me test 365 for divisibility by 2,3,5,6, and 10?

Question

There are 365 days in a non-leap year. Test 365 for divisibility by 2,3,5,6 and 10.

Answer 1

365/2 = 182.5

365/3 = 121.666

365/5 = 73

365/6= 60.833

365//10 = 36.5

the numer 365 is only divisible by 5 becos it does not leave a remainder unlike the other numbers

=)

Answer 2

The last digit of 365 is an odd number.So it is not divisible by 2.
3+6+5=16,which is not divisible by 3.So 365 is not divisible by 3.
The last digit of 365 is 5.So it is divisible by 5.
365 is not divisible by 2 So it annot be divisible by 6(Odd numbers are not divvisible by 6)
numbers ending with 0 ar only divisible by 10,So 365 is not divisible by 10

Answer 3

365 is divisible by 5 only (ends in 5)
Not 2 ---- last number isn't even
Not 3 --- the sum of the digits are not divisible by 3
Not 6 --- if it's not divisible by 2 and 3 then it's not divisible by 6
Not 10 --- doesn't end in 0

Answer 4

Get your calculator out and divide 365 by each of the numbers you have listed. For any that have no remainders after dividing, you kow that 365 is divisible by that number.

Answer 5

it's only divisible by 5, because it ends in a five.
Here's why it's not divisible by any of the others:
2-it's not even
3-the sum of the digits are not divisible by 3
6-it's not divisible by 2 and 3
10-it doesn't end in 0

Answer 6

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Answer 7

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