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i dont know how to get the answer on this question:
A person walks at a peed of 2.00m/s for 10.00 s, then walks at a speed of 1.50m/s for 8.00 s. What is the average speed of the person?
* By the way...m is meters and s is seconds
oh and the answer is 1.78 m/s but how do you get there?

2006-11-15 12:08:30 · 3 answers · asked by Anonymous in Education & Reference Homework Help

3 answers

2m/s x 10 s = 20 m
1.5 m/s x 8 s = 12 m
total m = 32 m
total t = 18 s
average speed is m/t = 32/18 = 16/9 =1.78 m/s

2006-11-15 12:13:22 · answer #1 · answered by ignoramus 7 · 0 0

Ok... You have to add it all up, then divide by the total time. So, 10 times 2 equals 20, and 1.5 times eight equals 12. 12+20 = 32, 32 divided by 18 equals 1.777778. To do averages, you add all the numbers together then divide by the total number of numbers you added. For instance, the average of 5, 6, 6 and 7 would be 6 because 5+6+6+7 = 24, then 24 divided by 4 (4 different numbers( equals 6!

2006-11-15 20:18:56 · answer #2 · answered by Zach S 5 · 0 0

The question really is: how far did he walk, and how long did it take him? Simply figure the distance walked - 32 meters - and the time it took - 18 seconds - and divide the distance by the time. The answer is really 1.7777... meters/second, but that rounds off to 1.78 as you said.

2006-11-15 20:24:41 · answer #3 · answered by Pete 4 · 0 0

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