I may be easier to use the quadratic formula but the original equation is 4x^2(4x squared) -44x + 63
2006-11-15 11:50:02 · 4 answers · asked by Julie J 1 in Science & Mathematics ➔ Mathematics
You have a system of equations as follows:
x + y = -44
xy = 252
y = -(44 + x)
-x(44 + x) = 252
x^2 +44x + 252 = 0
The roots of this equation give you the value of one number, and the other can be found by plugging in for x in y = 252 / x.
2006-11-15 11:59:59 · answer #1 · answered by Clueless 4 · 0⤊ 0⤋
Let x and y be the numbers. x+y=-44, xy=252; from the latter, y=252/x. Put this into the first, gettin x+252/x = -44; mult by x to get x^2+44x+252=0. From the quadratic equation, the numbers are -6.768 and -37.232. The numbers are also expressed as -22+2√58 and -22-2√58. Add together you get -22-22=-44; multiply them and get 22^2-4*58, 484-232=252.
2006-11-15 11:58:58 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
I dont know but the answer would probably be between 37.2+6.8=40 and 37.15+6.85=40...so im guessing one number would be 37point something and the second numer would be 6point something...i cant figure it out..when i mulitiplied the first one i got 252.9 and the second one i multiplied and got 254 so it would be between that im assuming
2006-11-15 12:10:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x = 9.308 or x = 1.692
2006-11-15 11:57:38 · answer #4 · answered by Megan M 2 · 0⤊ 0⤋