Question about Heat (Thermo)??

Question

Question: how much heat energy is needed to melt 32.0 grams of ice at 0 degrees celsius and then heat the water to 20 deg celsius?

Given: changeH(fusion), H20 = 6.02 KJ/mol; C(s) - specific heat - H2O = 4.1813 J/gk

My Approach:

i converted 4.1813 J/gk (1kJ / 1000J) = .0041813 KJ/gk

Then, i solved for the Energy

q = mc(s)changeT
q = (32.0 g)(.0041813 KJ/gk)(20 - 0 deg celsius)
q = 2.68 KJ <--------my answer! what do you get?

Answer 1

The number you have is for the temperature rise only. You have to add the heat of fusion for water which is 334.5 joule/g Multiply this by 32g to get 1.07*10^4 joule and add that to the 2.68*10^3 joule you have already computed. I get 13.4 kJ