What is the LCM for 48 and 116?

Answer 1

Figure the prime factorization of each number:
48 = 2 x 2 x 2 x 2 x 3
116 = 2 x 2 x 29

To get the lowest common multiple, take factors necessary to make either number. You need all the twos (2 x 2 x 2 x 2) and a three (3) and a twenty-nine (29).

Essentially you take each prime that appears (2, 3, 29). For each prime, figure the maximum number of times it appears in a single number. For example 2 appears 4 times for 48, so you keep 2^4 (2 x 2 x 2 x 2). The number 3 appears once in 48, so keep that (3). And 29 appears once in 116, so keep that (29).

Then you multiply them together:
2 x 2 x 2 x 2 x 3 x 29 = 1,392

Therefore:
LCM(48, 116) = 1,392

Answer 2

The best way to calculate LCM is to express each number as a product of one or more prime factors.

48 = 2 * 2 * 2 * 2 * 3 = 2^4 * 3^1
116 = 2 * 2 * 29 = 2^2 * 29^1

Then take the prime numbers used in each of these numbers along with the highest number of times each is used, the product of these is your LCM:

LCM (48, 116) = 2^4 * 3^1 * 29^1 = 1392

Answer 3

The GCD of 48 and 116 is 4, because if you
divide 4 into each, you get 12 and 29, which
are relatively prime.
So the LCM is 48*116/4 = 1392.
The LCM of 2 numbers is their product divided by their GCD.

Answer 4

1392

Answer 5

1392

Answer 6

Well i wont tell you the answer but tell you how to get it do a factor tree.