How do I write an equation of the line which has the given conditions?...?

Question

Slope = -9, passing through (2,4)

Answer 1

Given the slope of the line, m = -9, and a point (2, 4), we use the point-slope formula to obtain the equation of a line. That is:
(y - y0) = m(x - x0), where

(x0, y0) is the given point where a line passes through and m is the slope of the given line.

So we have the following:
y - 4 = -9 (x - 2)
y - 4 = -9x + 18
y = -9x + 18 + 4
y = -9x + 22

Thus, the equation of a line that passes through the point (2, 4) with a slope of -9 is y = -9x + 22.

Answer 2

The equation of a straight line is y=mx+b where m is the slope and b is the y-intercept.
You are given that m=-9. Now the equation is y=-9x+b; using the given condition, then
4=-9(2)+b=-18+b
Solve for b,
b=4+18=22
Here comes the line: y=-9x+22
Test it: y(x=2)=-9(2)+22=4, as advertised

Answer 3

the equation is y=mx+b, and fill int he blanks to find the y intercept.

4= (-9)2+b
4= -18+b
22=b
Then plug in the b
y= -9x+22 is your final equation

Answer 4

(y - 4)/(x - 2) = -9
(y - 4) = -9(x - 2)
y = -9x + 22

4 =? -9*2 + 22
4 =? -18 + 22
4 = 4

Answer 5

y=mx+b
4= -9(2)+b
b=22
y= -9x+22