Help with this problem please!?

Question

A group of nickels and dimes are found in a pocket. Together they add up to $4.45. There are 60 coins in total that have a difference of 24 in each number. Find how many nickels and dimes their are.

Answer 1

Set up like this:

x + y = 60
.05x + .10y = 4.45

Now you have 2 equations with 2 unknowns, which is easily solvable.

Multiply the first equation by .05 then subtract it from the second equation, like this:

.05x + .10y = 4.45
.05x + .05y = 3
--------------------------
0x + .05y = 1.45

Divide both sides by .05 to get:

y = 29

Now plug y=29 into your first equation to solve for x:

x + y = 60
x + 29 = 60

So, x = 31

ANSWER: 31 nickels, 29 dimes

CHECK YOUR ANSWER:

31 nickels = 1.55
29 dimes = 2.90
1.55 + 2.90 = 4.45 ← check!

I don't know what the "have a difference of 24 in each number" refers to in your original question. It seems misleading to me!

.

Answer 2

d + n = 60
10d + 10n = 600
10d + 5n = 445
5n = 155
n = 31 d = 29

What difference of 24? Your information is not consistent.