On a frictionless table, a glob of clay of mass 0.42 kg strikes a bar of mass 0.86 kg perpendicularly...?

Question

...at a point 0.26 m from the center of the bar and sticks to it. At what angular speed does the bar/clay system rotate about its center of mass after the impact?

Answer 1

The bar and the glob will rotate about the combined center of mass

the angular momentum of the glob with respect to the axis of rotation is .42 r v where r is the distance from the point of impact to the center of mass

angular momentum is conserved
you need to calculate the moment of inertia of the system about the center of mass,