I need help with these.2(2.5b -9) +6b =7, and12y = 2y +40, and 6(c +4) = 4c -18. thanks .
2006-11-15 10:26:11 · 6 answers · asked by catmuffin 1 in Science & Mathematics ➔ Mathematics
do the multiplication first, then add the variables, then solve the equation by getting the variable to one side , remember, you move numbers by adding their opposite to both sides
2(2.5b-9) + 6b=7
5b - 18 +6b=7
11b-18=7
+18 added to both side to move the -18
11b=7 +18
11b= 25
divide by -11 to both sides
b=25/-11
ps: oops was that a .2 at the beggining? if so, the answer for the start would be
.2(2.5b -9)
.5b -.9
2006-11-15 10:33:16 · answer #1 · answered by dlin333 7 · 0⤊ 0⤋
nicely Your fixing For X First You %. the backside quantity Thats no longer With A Variable (X) And Subtract It From the different right here pass's :) 4x+7=3x+18 ^ ^ they're further To the Variables, yet, we could Do the right opposite which could be Subtraction/. So... 7-18=11 this is How Your project could seem: 4x=3x+11 by way of fact We Moved the 7 To the splendid area Of The equivalent sign then you definately Do You Variables the backside one Is 3 And Plus Its on the area With The quantity That Doesnt Have A Vairable. So.... 4x-3x=x by no ability positioned 1x! x Is Already a million this is Your ending effect x=11 And Your complete :)) wish This Helped Ya ;) in case you prefer extra help.. Inbox Me :) xxxx
2016-10-22 04:01:37 · answer #2 · answered by haan 4 · 0⤊ 0⤋
a). 0.5b-1.8+6b=7
6b+0.5b=7+1.8
6.5b=8.8
b=8.8/6.5
b=1.35
b). 6c+24=4c-18
6c-4c= -24-18
2c= -42
c= -42/2
c=-21
2006-11-15 10:58:47 · answer #3 · answered by Lonely 2 · 0⤊ 0⤋
just get the variable to one side, then factor it out and solve
2006-11-15 10:28:19 · answer #4 · answered by aj 4 · 1⤊ 0⤋
ok, for the first one i got b= -1
the second one is y= 4
the third one is c= 21
hope it helps
2006-11-15 10:33:17 · answer #5 · answered by Stefanie A 2 · 0⤊ 0⤋
hhhhmmmmm......? try meditating....lol
2006-11-15 10:27:56 · answer #6 · answered by Anonymous · 0⤊ 1⤋