Calculate how much is needed to make appro. 500-mL of 0.04 M KMnO4?

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Calculate how much is needed to make appro. 500-mL of 0.04 M KMnO4?

2006-11-15 10:07:00 · 3 answers · asked by Geolady 1 in Science & Mathematics ➔ Chemistry

3 answers

Dissolve 3.2 g of KMnO4 in water to make 500 mL final volume. This will be 0.04M KMnO4 solution.

2006-11-15 20:57:01 · answer #1 · answered by chem_wiz 2 · 0⤊ 0⤋

Molarity = Mol/Volume
Molarity = .04M
Mol = ?
Volume = 0.5L
Therefore Mol = Molarity X Volume
= 0.04M X 0.5L
= 0.02 mol

2006-11-15 18:14:10 · answer #2 · answered by gordon_benbow 4 · 0⤊ 0⤋

How much what? Water? Grams of potassium permanganate?
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2006-11-15 18:10:29 · answer #3 · answered by Anonymous · 0⤊ 1⤋