Could you help me with this math problem?

Question

describe what happens to the graph of y = x^2 in the following situations.

*x is replaced with ( x - 3 )

*y is replaced with ( y - 2 )

Answer 1

Remember that the vertex of the parabola for y = x² is at (0,0). You can confirm this by putting x = 0 in and seeing that you get y = 0.

If you instead replaced x with (x - 3):
y = (x - 3)²

Notice how it would take a value of x = 3, to get y = 0. In other words, the whole graph, including the vertex would move 3 units to the right. The new vertex would be at (0, 3).

Similarly, if you replaced y with (y - 2):
y - 2 = x²

This is the same as:
y = x² + 2

So every value would move up 2. The graph would move two units up and the vertex would similarly move to (0, 2).

Case 1:
Parabola moves 3 units to the right -- vertex now at (3,0)

Case 2:
Parabola moves 2 units up -- vertex now at (0, 2)

Extra credit question for you:
What would happen if you did both?
(y - 2) = (x - 3)²

Answer 2

If x is replaced with x-3, the graph shifts 3 units to the right. If y is replaced with y-2, the graph shifts 2 units upwards

Answer 3

y = (x-3)^2

this means the x^2 shifts 3 units to the right (the change is on the x axis)

y-2 = x^2
y = x^2 + 2

this makes the graph move two units up (the change is on the y axis)

Answer 4

a) The vertex moves to 3,0

b) The vertex moves to 0,2

Answer 5

Wow you must be really smart wat math r u in? I'm already in Geometry and I have NO IDEA!