Practicing some algebra with nephew. Can't figure this though probably is simple. Can anyone give us your answer? We aren't sure the one we have is right- (75).
**Question:
The measure of
THANKS!
2006-11-15 09:17:06 · 8 answers · asked by southrngirl2724 3 in Science & Mathematics ➔ Mathematics
let t be the tens digit and o be the ones digit
t + o = 12
t = o + 2
substitute
(o + 2) + o = 12
gather like terms
2o = 10
divide by 2
o = 5
substitute this value into the equation t = o + 2
t = (5) + 2
t = 7
Since t = 7 and o = 5, 75 is the correct answer good work!
2006-11-15 09:23:41 · answer #1 · answered by TheTechKid 3 · 0⤊ 0⤋
y-2=x
x+y=12
Sub y-2 for x in 2nd equation
y-2+y=12
2y=14
y=7, x=5
Checking 7+5=12 and 7 is 2 greater than 5
By the way, what's
2006-11-15 17:26:44 · answer #2 · answered by captain173 2 · 0⤊ 0⤋
yea its right
if you add all possible numbers, only 75 has a number where the tens digit is 2 greater than the ones digit (75= 7-5) you get 2.
39= -6
48= -4
57= -2
66= 0
75= 2
84= 4
93= 6
2006-11-15 17:24:38 · answer #3 · answered by LaMathrick B 2 · 0⤊ 0⤋
represent the number using expanded notation so
and a = 2 + b
subsitute a with 2 + b
2b + 2 = 12
2b = 10
b= 5
a = 2 + b = 7
so yes 75
2006-11-15 17:22:31 · answer #4 · answered by rawfulcopter adfl;kasdjfl;kasdjf 3 · 1⤊ 0⤋
your answer satisfies the requirements. so you've got the right answer.
1) a + b =12
2) a = b + 2
(a is the tens digit, b is the ones digit)
2006-11-15 17:22:37 · answer #5 · answered by gggjoob 5 · 0⤊ 0⤋
Yes, 75 is correct!!!
2006-11-15 17:19:45 · answer #6 · answered by عبد الله (ドラゴン) 5 · 0⤊ 0⤋
That is correct.
2006-11-15 18:10:32 · answer #7 · answered by abcde12345 4 · 0⤊ 0⤋
go to hell loser
2006-11-15 17:21:17 · answer #8 · answered by abode 1 · 0⤊ 2⤋