Can some one help me with this math homework!!!! its 8th grade and im only in 7th?

Question

Given any random, 3-digit number, what is the probability that a number will be:

A) a multiple of 5

B) divisible by 2

C) a square number

Answer 1

A) 179/899
B) 449/899

Answer 2

Sorry, won't solve it for you, but I will give hints.

A probability can be written as the ratio of desired outcomes over possible outcomes. So if you're looking for any of 3 choices out of a total of 12 choices, the probability is 3 out of 12 = 3/12 = 1/4.

In this question, the choices is any 3-digit number, which is all of the numbers from 100 to 999 (900 numbers because 999 - 100 = 899, but you add one more since both 999 and 100 are valid).

For A), find all the numbers between 100 and 999 (inclusive) that are divisible by 5 (i.e., ends in 0 or 5) and divide by 900.

For B), find all the numbers between 100 and 999 (inclusive) that are divisible by 2 (ends in 0, 2, 4, 6, or 8) and divide by 900.

For C), find all numbers that are squares. 100 is a square (10^2).

Answer 3

well, I hope nobody just gives you the answers because you are smart enough to get these

first, we are only talking about numbers 001 to 999
or do we exclude all the numbers less than 100?
so not including 1000, how many numbers are divisible by 5, in other words what divided by 5 would give you the correct answer?
Second, all even numbers are divisible by 2, so how many even numbers is that?
Third, square numbers can be tricky. What are sqare numbers? the product of a number multipluied by itself, such as 4x4 is 16, 8x 8 is 64, 16 and 64 are both square numbers
Which square is the biggest but less than 999?
you could proceed like this: 10x10 =100, 11x11= 121, 12x12 =144 or start from the biggest square number you know is less than 1000 like 900, 30 x30 = 900, so its at least 30 square numbers (minus the squares less than 100, what is that? 8? 9?)
okay?
BTW Ruth is WRONG!
I just reread the question, if these are probablities, then they should all be written as a ratio, right?

Answer 4

Well basically you just have to think
a) how many numbers that are multiples of 5's are there between 100 and 999 (don't forget to include the 100)

b) how many numbers that are multiples of 2's are there between 100 and 999 (don't forget to include the 100)

c. How many squares between 100 and 999 (dont' forget to include the 100)

Then whatever answer you get, the probabilty will be that number out of 899

Answer 5

21 = (-7/2) W you may discover which style, even as higher with -7/2, provides a million. the answer, through definition, is the reciprocal. So multiply each and each and every aspect of the equation through the reciprocal of -7/2, or -2/7: 21 (-2/7) = (-7/2) W (-2/7) on the left aspect, a 7 receives cancelled out, and on the right aspect, each and everything cancels (that is the reason) 3 (-2) = W Now simplify W = -6

Answer 6

a.111.b. 222 c. 121. Not too sure if this is what you want.