English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

4 answers

well...lets call your known volume V. so...what kind of shape are we dealing with...eh, lets claim we are dealing with a sphere...we know the volume of the sphere is determined by v=(4/3)*pi*r^3 so we could solve for r (the radius).

so....

V=(4/3)*pi*r^3
r=((3V)/(4pi))^(1/3)

we can now substitute that r into our surface area of a sphere equation....which is SA=4*pi*r^2, so we would have

SA=4*pi*((3V)/(4pi))^(2/3)

a similar series of actions would occur for any other shape

hope this helps,

Matttlocke

2006-11-15 07:45:06 · answer #1 · answered by matttlocke 4 · 0 0

You would need to know the shape of the object and whether or not it was symmetrical. Spherical would be the least possible surface area for any known volume.

2006-11-15 07:34:42 · answer #2 · answered by Anonymous · 0 1

You need a converter! Go to dollar tree store!

2006-11-15 07:33:36 · answer #3 · answered by Vladimir S 2 · 0 1

search the internet

2006-11-15 07:32:49 · answer #4 · answered by Anonymous · 0 1

fedest.com, questions and answers