A fair die is rolled and the number of dots showing is recorded. A random variable X is defined to be 1 if the result is greater than 3, and 4 if the result is less or equal to 3.
a. 1/2
b. 5/2
c. 9/2
d. 11/2
e. none of the others
2006-11-15 07:29:58 · 3 answers · asked by girlsidra 1 in Science & Mathematics ➔ Mathematics
x1*p(x1) + x2*p(x2)
x1 = 1 for event dots> 3,
x2 = 4 for event dots<=3.
These are equally probable because there are 6 dots on the die.
1*(1/2) + 4*(1/2)
2006-11-15 07:37:02 · answer #1 · answered by modulo_function 7 · 1⤊ 0⤋
do your own homework!!
Sheesh
think about it.
how many sides on a fair die (this is not Dungeons and Dragons so we can safely assume 6)
so with a 6-sided die and if the number rolled are one of the numbers 4,5,6 (which co-incidentally is half of 6) it gets a value of 1 and if its numbers 1,2,3 it gets a value of 4.
so its a 50:50 chance that a value of 1 or 4 is produced (kinda like flipping a coin) so what would happen if first a 1was rolled on the die and after that a 6 was rolled - what would x be equal to?
2006-11-15 07:37:44 · answer #2 · answered by S1 tower 1 · 0⤊ 0⤋
i dont get it......but still 10x 4 d points
2006-11-15 08:12:09 · answer #3 · answered by wendy 2 · 0⤊ 0⤋