Sea level is about 6.4*10^6 meters from the center of Earth.
2006-11-15 07:00:42 · 4 answers · asked by disgracedfish 3 in Science & Mathematics ➔ Mathematics
Since 50 grams is .05 kg, at sea level the weight is .05 * 9.80665 = .4903325 N.
Assuming a sea level radius of 6400 km, at 6401.5 km the reduction in gravitational force is (6401.5^2) / (6400^2) = 1.000469
And the weight would be .490103 Newtons.
2006-11-15 07:11:54 · answer #1 · answered by Keith P 7 · 0⤊ 0⤋
You can treat the earth as a point mass. Using the F=Gm1m2/r^2 relationship you can get the value for g at your elevation. Note that you can just use scaling so that you don't have to calculate:
gh/ge = (re/rh)^2 where ge is g at earth's surface(re), gh is g at height rh
(6.4*10^6/(6.4*10^6+1500)^2 =
2006-11-15 15:07:23 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
weight at sea level=50/1000*9.8 N
=0.49 N
you will have to find the 'g' at 1500 m height and then multiply it by the mass that is 0.05 kg to get the weight
2006-11-15 15:05:12 · answer #3 · answered by raj 7 · 0⤊ 0⤋
When the object is in free fall, the weight is exactly 0 N,
because it does not force on any bottom.
When it hangs the weight is mg = 0.050 g x 9.8 N/kg = 0.49 N.
Th
2006-11-15 15:32:50 · answer #4 · answered by Thermo 6 · 0⤊ 0⤋