Twice the sum of a number and 3 is the same as 11 increased by the number. find the number.?

Answer 1

"Twice" --> 2 *
"sum of a number and 3" -> (n + 3)
"is the same as" --> =
"11 increased by the number" --> 11 + n
2(n + 3) = 11 + n

Distribute the 2 through the parentheses:
2n + 6 = n + 11

Get like terms together (subtract n and subtract 6):
2n - n = 11 - 6

Simplify:
n = 5

Checking:
The sum of 5 and 3 is 8.
Twice this is 16.

11 increased by 5 is 16, which is the same.

So the number is 5.

Answer 2

The best way to tackle this problem is to break it apart.

Let x = number

"the sum of a number and 3" -> x + 3
"twice the sum of a number and 3" -> 2(x + 3)
"is" -> =
"11 increased by the number" -> 11 + x

Put it all together:
2(x + 3) = 11 + x
2x + 6 = 11 +x
x + 6 = 11
x = 5

Hope this helps.

Answer 3

The number is 15

Answer 4

2(n+3) = 11+n

2n+6 = 11+n

n = 5

Answer 5

2(3+x)=11+x
6+2x=11+x
-x -x
6+x=11
-6 -6
x = 5

CHECK
2(3+5)=11+5
2(8)=11+5
16=16

Answer 6

Let the unknown number be "x", and then set up the problem this way:
2(x+3) = 11+x
2x + 6 = 11+x
Take away 1x from each side, leaving...
x+6 = 11
x = 5

Answer 7

2(n+3)=11+n
2n+6=11+n
n=5

Answer 8

Let x -= the number

2x + 3 = 11 + x
x = 8

Answer 9

this is the equation:
2(x+3)=x+11
2x+6=x+11
2x=x+5
x+5

others have said 8 but that is not the twice the sum of a number and three. that is just twice a number plus three.

Answer 10

let the no be x
given
2x+3=x+11
adding -3
2x=x+8
adding -x
x=8
the no is 8
check
16+3=8+11