Maths probability problem?

Question

Jim spins a biased coin.
The probability that it will land on heads is twice the probability that it will land on tails.
Jim spins the coin twice.
Find the probability that it will land once on heads and once on tails.
Please explain your steps simply and carefully

Answer 1

I believe the answer is 44.44%.
2/3 is the prob for heads and 1/3 is the prob for tails.

There are only two possible out comes to get this...heads then a tails...or tails then heads.

2/3*1/3 is the outcome where you get a head then a tail.
Plus 1/3*2/3 where you get a tail then a head.

So basically the answer is 2/3*1/3 + 1/3*2/3 or (2/3*1/3)*2 = 4/9

Answer 2

The number of possible outcomes is 2^2 = 4
T,T
T,H
H,T
H,H

2 of 4 combinations will land one H and one T.

P(H)*P(T)*2 = (2/3)(1/3)(2) = 4/9

Answer 3

p(head)=2/3
p(tails)=1/3

p (Head-Head)=(2/3)x(2/3)=4/9
p( Tails-tails)= (1/3)x(1/3)= 1/9

Answer your question= 1-(4/9+1/9)= 4/9