mean n between 7/3 and 5
7/3
2006-11-15 06:09:49
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answer #1
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answered by Anonymous
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There are two integer solutions:
n=3 (3n=9, 7<9<15)
n=4 (3n=12, 7<12<15)
2006-11-15 14:14:57
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answer #2
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answered by keith 2
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You probably have to figure out what n can equal.
7 < 3n < 15
This means that 7 is less than 3n and 3n is less than 15.
If you divide everything by 3, you get
7/3 < n < 15/3
This means that 7/3 is less than n and n is less than 15/3.
In other words, you know that n is between 7/3 and 15/3.
I hope that helps.
2006-11-15 14:11:35
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answer #3
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answered by Math Helper 3
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Look at double inequalities like this: break it up into two...
7<3n
3n<15
It means the set of numbers in which 7 is less than 3n AND 3n is less than 15
then you can solve each one separately.
7<3n
7/3
3n<15
n<5.
Put them together an it is the set of numbers which n is greater than 7/3 or less than 5.
To check your answer, pick a number between 7/3 and 5 and plug it back in.
2006-11-15 14:10:47
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answer #4
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answered by prudentzeta 2
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The n is a variable that when found, is multiplied by the 3. The equation is stating that 7 is less than 3n (3 times the value of n) and 15 is greater than 3n.
2006-11-15 14:09:38
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answer #5
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answered by graduatecj08 3
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7<3n<15
It means that the value of 3n is greater than 7 but less than 15.
If you divide all terms by 3 you get:
7/3
This tells you that value of n is greater than 7/3 but less than 5.
The value of n is restricted to lie between 7/3 and 5.
n cannot be equal to 5 or greater than 5.
n cannot = 7/3 or be less than 7/3
2006-11-15 14:18:50
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answer #6
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answered by ironduke8159 7
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It means that 3n > 7 AND 3n < 15.
2006-11-15 14:08:34
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answer #7
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answered by Anonymous
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7 is less than 3n but 3n is less than 15
2006-11-15 14:08:41
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answer #8
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answered by psycho 3
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7<3n<15
divide all terms by 3
7/3
that means any number that is more than 7/3 and less than 3 is the solution
2006-11-15 14:09:26
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answer #9
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answered by 7
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7 < 3n < 15
The character < means is less than
7 < 3n, means 7 is less than 3n
3n < 17, means 3n is less than 15
- - - - - - - -s-
2006-11-15 14:45:39
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answer #10
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answered by SAMUEL D 7
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