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There are 2 containers filled with gas. In 1st container there's pressure of 10 bar and the volume is 300 liters in the second one the volume is 400 liters and the pressure 3 bar. How can I calculate what pressure it will be when the gases containedin these 2 containers mix together creating one container composed of the former 2 the volume is obviously 600 liters. V1=300 l p1=10 bar V2=400 l p2=3 bar V(together)=600 l p=?
srry 4 my english

2006-11-15 06:02:05 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

Assuming temperature is static, I think Dalton's Law would apply:
The sum of all the partial pressures.

P(gas 1)V(vol 1) = P(new gas 1)V(together)
10 bars * 300L = ? bars * 600 L
P(new gas 1) = 5 bars

P(gas 2)V(vol 2) = P(new gas 2)V(together)
3 bars * 400L = ? bars * 600 L
P(new gas 2) = 2 bars

P(together) = P(new gas 1) + P(new gas 2)
P(together) = 7 bars

2006-11-15 08:03:49 · answer #1 · answered by thubanconsulting 3 · 1 0

sure, that equation is genuine in spite of the reality that it is often written as: P1V1/T1=P1V2/T2 P=tension V=quantity T=temperature(Kelvins) the type you wrote it is likewise ultimate suited nevertheless. you could incorporate moles into the equation. P1V1/T1n1=R=P2V2/T2n2 P=tension V=quantity T=temperature(Kelvins) n=moles R=gas consistent(8.31 kPa x L/ok x mol) The gas consistent could have distinctive values reckoning on the instruments of tension you employ so in case you employ atmospheres, mmHg etc it ought to have a distinctive fee.

2016-12-14 07:46:01 · answer #2 · answered by zell 4 · 0 0

U don't need all that just some good regulators and flow meters. u know what ratio u want .

2006-11-15 08:24:32 · answer #3 · answered by JOHNNIE B 7 · 0 1

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