2006-11-15 05:59:00 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Gopal screws up the arithmetic again. The cube root of 3.5 is 1.518294486.
2006-11-15 06:12:15 · answer #1 · answered by ? 6 · 0⤊ 0⤋
The correct answer is NO.
Is this a trick question? Any container that starts with a specific volume remains at that volume no matter what heat, cold, pressure, or speed of light. In other words, it is impossible for a container with a volume of 3.5 cubic feet to equal 6 cubic ft. Has anyone else caught this? A quick scan says no one did..
To stop poking fun at you . . .
Assume a cube w/volume of 3.5 cubic ft.. Find the cube root of 3.5, multiply that answer by 2.54, and that answer cubed will give you the cubic whatever in metric measurements. Guess what? The answer is approximately 6 cubic metric something or others.
This once math whiz forgot a lot of math over many loooooooong years. Thaks for giving my mind some excercise.
2006-11-15 14:17:25 · answer #2 · answered by bob h 5 · 0⤊ 0⤋
If the box isn't a cube, the answer can be relatively easy. Find three numbers that when multiplied equal 3.5 or 6.0. The 3.5 cu.ft. box could be 3.5 ft by 1ft by 1ft. The 6.0 cu.ft box could be 2ft by 3ft by 1ft.
If the box needs to be a perfect cube, then you need to find the cube root of the number. The 3.5cu.ft box would be 1.51829449 ft by 1.51829449 ft by 1.51829449 ft. The 6.0 cu.ft. box would be 1.81712059 ft by 1.81712059 ft by 1.81712059.
2006-11-15 14:10:23 · answer #3 · answered by Earl W 2 · 1⤊ 0⤋
The boxes can be of any size in feet aslong as when the length, width and depth are multiplied gives 3.5 or 6
So a 6cft can be a box of l=2, w=3, d=1 or l=1,d=1,w=6 etc..
2006-11-15 14:04:11 · answer #4 · answered by Oz 4 · 0⤊ 0⤋
3.5 cu. ft and 6.0 cu. ft respectively.
If you are referring to the sides then we need know what are the constrains.
For a example the base of such box is an integer square then for 3.5 Cu Ft we have
1x1=1sf and 1sf x 3.5ft=3.5 cu ft
and for 6 cu ft box
either we have 1x1=1sf and 1sf x 6 ft=6 cu ft
or
2x2=2sf and 4 sf x 1.5 ft=6 cu ft
So as you can se constrains must be given or you can use proper solution given by other people however their solutions are one many if not infinite.
2006-11-15 14:04:03 · answer #5 · answered by Seductive Stargazer 3 · 0⤊ 1⤋
assum that the box is a cube which has equal sides
A=S^3
3.5 ft^3=S^3
S=1.518 ft
6.0 ft^3=S^3
S=1.817 ft
2006-11-15 14:03:42 · answer #6 · answered by 7 · 0⤊ 0⤋
6 cft box will be 3' long 2' wide and 1' high
3.5 cft box will be approx 1.45'*1.45'*1.45'
2006-11-15 14:02:05 · answer #7 · answered by raj 7 · 0⤊ 0⤋