2006-11-15 05:54:45 · 6 answers · asked by ♥ kellycakes ♥ 1 in Science & Mathematics ➔ Mathematics
area of a regular hexagon=3rt3/2 *a^2
=3rt3/2*24^2
=72*12rt3
=864rt3 cm^2
2006-11-15 05:58:06 · answer #1 · answered by raj 7 · 2⤊ 0⤋
The area of a regular hexagon is 1/2 the apothem times the perimeter.
The apothem is 12*sqrt 3 because it is the long leg of a 30 -60 -90 degree right triangle.
The perimeter is just 6* 24=144 cm
The area is 0.5* 144 * 12 * sqrt 3= 864sqrt 3 cm^2
An approximate value is 864*1.732 = 1496.45 cm^2
2006-11-15 14:07:29 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
A=1/2*apathem*Perimeter
2006-11-15 14:04:44 · answer #3 · answered by 7 · 0⤊ 1⤋
maybe this will help. your hexagon can be divided into 6 equilateral triangles with 24cm/side. so then you just have to figure the area of triangle and multiply by 6
2006-11-15 13:58:38 · answer #4 · answered by gggjoob 5 · 0⤊ 1⤋
Area of a regular polygon of n sides
=[1/4]*n*b^2*cot Pi/n
n=6,cotPi/6=sqrt3
area
=1/4*6*24*24*sqrt3
=1.5*576*1.732
=1496.448 sq.cm
2006-11-15 14:10:40 · answer #5 · answered by openpsychy 6 · 0⤊ 1⤋
For a regular hexagon:
A = (2.59808)(a^2)
A = (2.59808)(24^2)
A = 1496.49408 cm squared
2006-11-15 14:04:29 · answer #6 · answered by Anonymous · 0⤊ 1⤋