2006-11-15 04:58:22 · 32 answers · asked by Anonymous in Entertainment & Music ➔ Comics & Animation
smithers
2006-11-15 04:59:29 · answer #1 · answered by markhatter 6 · 0⤊ 0⤋
List of Simpson's gay characters are,
1: Patty Bouvier
2: Grady &
3: Julio, the two homosexuals that Homer briefly lived with in "Three Gays of the Condo"
4: John (nic/nack store)
5: Waylon Smithers
6: Lenny Leonard? for idolising Carl, he he.
7: The gay steel mill workers
8: Rod and Todd have appeared gay in the future
9: Well there is a thriving gay quarter in springfield so there must be plenty more!
2006-11-15 06:21:18 · answer #2 · answered by Raven Shiranui 3 · 2⤊ 0⤋
Mr Smithers
2006-11-19 00:43:34 · answer #3 · answered by Funke123 1 · 0⤊ 0⤋
Smithers, Mr Burns Mate.
2006-11-15 04:59:52 · answer #4 · answered by Ste444 4 · 0⤊ 0⤋
Which One. There have been like 5 of them.
-Smithers
-the two guys that homer moved in with. one was bloned the other had black hair.
-also the episode where homer thought bart was going gay, so homer takes bart to this "Manly" steel mill. That gay formen said "We Work Hard, We Play Hard." A disco ball drops, Some song comes out and the steel mill becomes a gay club. LOL.
2006-11-15 06:46:35 · answer #5 · answered by ray_of_the_day 1 · 1⤊ 0⤋
Smithers
2006-11-15 05:09:24 · answer #6 · answered by OJW3381 2 · 0⤊ 0⤋
Smithers
2006-11-15 05:00:19 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Smithers
2006-11-15 04:59:58 · answer #8 · answered by colin050659 6 · 0⤊ 0⤋
Smithers, Montgomery Burn's Man Friday.
I think Ned Flanders is a bit gay, too, & Carl & Lenny have a very interesting relationship, as well.
2006-11-15 08:31:02 · answer #9 · answered by lee17201 3 · 0⤊ 0⤋
Smithers is supposed to be Gay but they never really come out and say it.
Marge's sister Patty has come out as gay officially in the show.
2006-11-15 05:03:21 · answer #10 · answered by Anonymous · 1⤊ 0⤋
Mister Waylon Smithers! He is obviously attracted to Mr. Burns, the skeletal, ancient owner of the nuclear plant.
2006-11-15 05:02:00 · answer #11 · answered by Anonymous · 2⤊ 0⤋