9x56=504 5+0+4=9
2006-11-15 04:28:00 · 15 answers · asked by VEDBHUSHAN T 1 in Science & Mathematics ➔ Mathematics
you take any number which is divisible by nine
sum of its digits will be nine or any multiple of nine
e.g.
99 9+9=18 1+8=9
keep on suming the digits if the sum comes to be more than one digit it will at last become nine
e.g.
123456789 1+2+3+4+5+6+7+8+9=45=4+5=9
hence any number you multiply by nine you will get the sum 9 finally
2006-11-15 15:54:54 · answer #1 · answered by vinit bansal 1 · 0⤊ 1⤋
9*6=54 5+4=9
2006-11-15 05:58:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Take any real number natural, decimal except zero, the sum of digits will always be 9.
eg:3
=>9 * 3=27
=>2+7=9
eg:0.45
0.45 * 9=4.05
add digits:4+0+5=9
2006-11-15 22:19:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋
9*8=72
7+2=9
2006-11-15 17:20:31 · answer #4 · answered by Goldie d 1 · 0⤊ 0⤋
9X90=810 8+1+0=9
2006-11-15 04:31:38 · answer #5 · answered by marindians 1 · 0⤊ 0⤋
The whole Nine(9) table.
9x1=9
9x2=18 1+8=9
9x3=27 2+7=9
9x4=36 3+6=9...............so on
2006-11-15 16:24:54 · answer #6 · answered by arpita 5 · 0⤊ 0⤋
The whole Nine(9) table.
9x1=9
9x2=18 1+8=9
9x3=27 2+7=9
9x4=36 3+6=9...............so on
2006-11-15 05:28:01 · answer #7 · answered by bapuni 2 · 0⤊ 0⤋
U take any number the product that will come after multiplying 9 and anyother number it's sum will be always 9 it is the divisibility property of it
as if sum of all numbers is divisible by 3 than that no. is divisible by 3
2006-11-15 04:46:46 · answer #8 · answered by Baku 2 · 0⤊ 0⤋
Yes, that is true for all numbers. If you want to know if a large number is divisible by 9, this is how you do it. add the digits. If the sum of the digits is divisible by 9, the original number is as well. If not, it isn't. This also works for division by 3.
2006-11-15 04:41:58 · answer #9 · answered by yupchagee 7 · 0⤊ 0⤋
9 * 1 = 9
(Any number times 1 is equal to the number.)
2006-11-15 04:30:37 · answer #10 · answered by kc_warpaint 5 · 0⤊ 0⤋