The Earth is 150 million kilometers from the sun, & it takes the Earth 1 year to go around the sun. An asteroid that is 632 million kilometers from the sun is in a circular orbit around the sun. Assume 365 days per year.
What is the period, Ta, of the asteroid orbit in years?
Also, what is the orbital velocity of the asteroid in m/s?
2006-11-15 02:57:27 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
This is all the info given, and I have been assured it can be answered. Any ideas??
2006-11-15 03:12:17 · update #1
Kepler's third Law: T^2 is proportinal to R^3
T= time period, R =distance in your case
Ta=sqrt[ Te^2 x (Ra/Re)^3 ]
As for orbital velocity, you now know the time period(Ta) and can calculate circumference(C=2.PI.Ra) of the orbit. Velocity is C/Ta
2006-11-15 05:24:36 · answer #1 · answered by Defunct 2 · 0⤊ 0⤋
I don't think one can determine that without the velocity of the asteroid. Plus orbits are normally elpitical not circular.
2006-11-15 11:07:23 · answer #2 · answered by Albert 6 · 0⤊ 0⤋
Too much to explain....
Hope these links will help you
2006-11-15 12:08:46 · answer #3 · answered by MobiGuru 2 · 0⤊ 0⤋