If z=1+i
then what is its trigonometric form?
And how to get the argument (i.e. Tita 0)???
2006-11-14
22:40:46
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6 answers
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asked by
HellBoy
2
in
Science & Mathematics
➔ Mathematics
Yes, if this is the ans 1/root(2){cos 45 + i sin 45} then how do you get 45 deg?
2006-11-14
22:48:29 ·
update #1
Thanks a ton math_kp! You solved my Q totally!
And yes, Hy you are right you have to express it in radians!
Thank you all!
2006-11-14
22:58:32 ·
update #2
in trigonomertic form
z = r cos t + ir sin t = 1 + i
so r cos t = 1
r sin t = 1
square and add r^2 = 2
so r = sqrt(2)
now cos t = 1/sqrt(2) and sint = 1/sqrt(2)
so t = pi/4 (as cos pi/4 = 1/sqrt(2) and sin is also positive so 1st quadrant)
so t = pi/4 and r = sqrt(2)
2006-11-14 22:52:56
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answer #1
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answered by Mein Hoon Na 7
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There's an awful lot of blah-blah going on here.
Look, in general, when z=a+bi then tanθ=b/a, so
here tanθ=1/1, hence θ=45 degrees or more properly, Ï/4.
The length L is b/sin(Ï/4) or a/cos(Ï/4) so here we have
L=1/sin(Ï/4)=1/(1/2^(1/2) = 1.414 or 2^(1/2).
You could also use the Pythagorean theorem and say
L=(1^2 + 1^2)^(1/2) = 2^(1/2).
On the complex plane this is L{cos(Ï/4) + (i)sin(Ï/4)} and
in polar form it's (L,(Ï/4)).
Now here's a hint. In math we tend to use the same angles a
lot. They are the 45d, 30d and 60d. In radians : Ï/4, Ï/6 and Ï/3
respectively. In a right triangle the ratio of the sides is side to side to hypotenuse as follows:
for a 45d(Ï/4) - 1:1:2^(1/2)
for a 30,60 (Ï/3, Ï/6) - 1:2:3^(1/2) .
There's also the 3:4:5 rt triangle and occasionally the 5:12:13.
Get familiar with these ratios, you can usually get around
the trig with them..
2006-11-15 00:55:44
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answer #2
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answered by albert 5
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On an Argand diagram, the point (x,y)
represents the complex number z = x + iy.
Your complex number is z = 1 + i, or 1 + i1,
which means x = 1 and y = 1.
Now, x = r*cos(theta) and y = r*sin(theta)
and r = sqrt(x^2 + y^2) = sqrt(1 + 1) = sqrt(2).
But if x = y = 1, then r*cos(theta) = r*sin(theta)
Dividing both sides by r*cos(theta) gives :
1 = tan(theta). Therefore, theta = pi / 4 rads.
The polar form is : z = x + iy = r[cos(theta) + i*sin(theta)]
Therefore, z = 1 + i1 = sqrt(2) * [cos(pi / 4) + i*sin(pi / 4)]
2006-11-14 23:15:45
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answer #3
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answered by falzoon 7
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You mean its the polar form?
Then it would be 1/root(2){cos 45 + i sin 45}
2006-11-14 22:46:25
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answer #4
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answered by Thilina Guluwita 4
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For z = x + iy,
tan(arg) = y/x
I believe it's wrong to use degrees for expressing complex numbers in this form. In this case
arctan(y/x) = arctan 1
= pi/4
PS Yeah, I agree, Math KP should get the points.
2006-11-14 22:53:05
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answer #5
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answered by Hy 7
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z = 1 + 1i
z = V2 {(1/V2) + (i/V2) }
z = V2{cos45 + i sin45}. The angle in degrees.
Th
2006-11-14 23:05:56
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answer #6
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answered by Thermo 6
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