write a shell script for count number of vowels from a file?

Answer 1

I can tell you the logic. Try testing as I do not have a Unix box right now with me to check.

read word
lengthofword=`echo $word | wc -c`
cntr=1
no_of_vowels=0
while($cntr -le $lengthofword)
do
{
ltr=`cat $word | cut -c$cntr`
if [ $ltr = "a" -o $ltr = "e" .... $ltr = "u" ]
then
no_of_vowels=`expr $no_of_vowels + 1 `
cntr=`expr $cntr + 1 `
}
done

Answer 2

Shell Script Count

Answer 3

it would be a simple one liner

vowel_no= cat file.txt | tr -cd \aeiou\ | wc -c
echo $vowel_no

cat file.txt prints the file out which is piped the the translate command which deletes all the everything else other than the vowels (this is done by the complement c) and the output of this is piped to wc -c does a character count