What is the value of the two variable? Show solution?

Question

5x - 28 = 12 + 3y

x = ?

y = ?

Answer 1

This equation has a solution when x = 0 or y = 0

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x = 0

5x - 28 = 12 + 3y

5(0) - 28 = 12 + 3y

0 - 28 = 12 + 3y

- 28 = 12 + 3y

- 28 - 12 + 12 + 3y - 12

- 30 = 3y

- 30/3 = 3y/3

- 10 = y

The answer is y = - 10

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y = 0

5x - 28 = 12 + 3y

5x - 28 = 12 + 3(0)

5x - 28 = 12 + 0

5x - 28 + 28 = 12 + 28

5x = 30

5x/5 = 30/5

x = 6

The answer is x = 6

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x = 6

y = - 10

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The solution set is { 6, - 10 }

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Answer 2

You can not find value for two unknown variables, with one equation. Thats the law.

You can not solve n equation for n+2 variables.

Otherways, if you assume any values for one of the variables then you get value of other variable. thats the only thing you can do.

For example :
Assuming x=2 => 10 - 28 = 12 + 3y
=> 10 - 28 - 12 = 3y
=> 10 - 28 - 12 = 3y
=> -30 = 3y
=> y = -30/3
=> y = -10

For example :
Assuming y=2 => 5x - 28 = 12 + 6
=> 5x = 28 + 12 + 6
=> 5x = 46
=> x = 46/5

Answer 3

5x - 28 = 12 + 3y
5x = 40 + 3y
x = 8 + 0.6y

The equation doesn't have only one solution.
Examples: x = 11, y = 5 or x = 20, y = 20

Answer 4

5x -28 = 12 + 3y

5x = 40 + 3y

x = 8 + (3/5)y

and

3y + 12 = 5x - 28

3y = 5x -40

y = (5/3)x - (40/3)

Answer 5

y = 5x/3 - 40/3

y is a dependent variable, it's value depends on the value of x

x can equal anything.

So for example if x=10 then y = 50/3 - 40/3 = 10/3

Answer 6

in this equation, there are infinitely many solutions, So the the domain would be the set of all reals, and the range is the set of all reals. There is no way to have exactly one solution without having a second linearly independent(from the given equation) equation. This would enable for there to be only one solution to your system.

Answer 7

You need a second equation with either x, y, or both x and y to solve this problem. With the second equation, solve it for, say x, and plug that equation into the first one, which enables you to solve for y.

Answer 8

need 2 equations